Question 704858
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Let *[tex \LARGE x] represent the amount invested in the 8% account.  Then the amount invested in the 6% account has to be *[tex \LARGE 7000\ -\ x].  The amount of interest earned on the 8% account is then *[tex \LARGE 0.08x] and the amount earned on the 6% account is *[tex \LARGE 0.06(7000\ -\ x)].  Finally, the sum of these two amounts has to be $520, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.08x\ +\ 0.06(7000\ -\ x)\ =\ 520]


Solve for *[tex \LARGE x] then calculate *[tex \LARGE 7000\ -\ x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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