Question 704816
A store is selling two different types of cheese. One type sells for $3.75 a pound and a second type sells for $4.55 a pound. How many pounds of the $3.75 cheese would the store need to mix together with the $4.55 cheese to get a 45-pound block mixture that sells for $4.05 a pound? 
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Equations:
a + b = 45 lbs
375a + 455b = 405*45
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455a + 455b = 455*45
375a + 455b = 405*45
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80a = 50*45
a = (5/8)45
a = 28.125 lbs (amt. of $3.75 cheese needed)
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Cheers,
Stan H.