Question 704404
First find the factors of 4 form the {{{4X^2}}}
The factors of 4 are: 1,2,2,4
Next Find the factors of 5 (the constant)
The factors of 5 are: 1,5
Note that the 5 is positive that means that the factors have to both be positive or both negative.
Now use the factors of 4 and the factors of 5 to come up with the 12X
2*5 + 2*1 = 12
So {{{4X^2 + 12X + 5}}} can be rewritten as {{{(2X + 5)*(2X + 1)}}}
-------------------------------------------------------
Now we have to solve for each part of the equation.
The equation equals zero when either of the parentheses equal zero.
{{{2X + 5 = 0}}}
Subtract 5 from both sides
{{{2X = -5}}}
Divide both sides by 2
{{{highlight(X = -5/2)}}}
-------------------------------------------------------
{{{2X + 1 = 0}}}
Subtract 1 from both sides
{{{2X = -1}}}
Divide both sides by 2
{{{highlight_green(X = -1/2)}}}