Question 704235
 {{{y/((2y-5)) = 5/y}}}
Cross multiply
y*y = 5(2y-5)
y^2 = 10y - 25
Arrange as a quadratic equation on the left
y^2 - 10y + 25 = 0
Factors to
(y-5)(y-5) = 0
solution
y = 5
:
:
Confirm this in the original equation, replace y with 5
{{{5/((2(5)-5)) = 5/5}}}
{{{5/5}}} = {{{5/5}}}