Question 704260
How to set it up:

How much fluid ounces of the new mixture?  (5 + 11) fluid ounces.

(Amount of alcohol from the 2% solution + amount of alcohol from the 66% solution)= Amount of just the alcohol.


%Alcohol_Mixture=100*(Amount of alcohol)/(Amount of mixture)
Alternatively,
Fraction_as_alcohol=(Amount of alcohol)/(Amount of mixture)


{{{(5*(0.02)+11*(0.66))/(5+11)=F}}}, where F is the fraction of mixture as alcohol.