<PRE><B>Question 704243</B>
Let w = the width of the walk.
Then the two dimensions of the walk and pool are both (11 + 2*w).
The area of the walkway is the total area minus the pool area or
(1) (11 + 2*w)^2 - 11^2 = 203 or
(2) 121 + 44*w + 4*w^2 - 121 = 203 or
(3) 4*w^2 + 44*w - 203 = 0
Use the quadratic equation to get the positive value of the width as
(4) w = 3.5
Check this value in (1)
Is ((11 + 2*3.5)^2 - 11^2 = 203)?
Is ((11 + 7)^2 - 121 = 203)?
Is (18^2 - 121 = 203)?
Is (324 - 121 = 203)?
Is (203 = 203)? Yes
Answer: The width of the walk is 3.5 feet.</PRE>