Question 704073
Let first no. =x
    second no. =x+y
    third no. =x+2y
given,
 x+x+y+x+2y=27
 3x+3y=27
 x+y=9
 
also given,
 x(x+y)=36
dividing both,

 x(x+y)/x+y = 36/9
 x=4
 y=5

Ans. First no.=4, Second no.=9, third no.=14