Question 704032
b = base and altitude = 5b/3

Area = 1/2(b)(h) = 1/2(5b/3)(b) = (5b^2)/6

Altitude increased by 4 = 5b/3 + 4

Base decreased by 2 = b - 2

(5b/3 + 4)(b - 2) = (5b^2)/3

5b^2/3 - 10b/3 + 4b - 8 = (5b^2)/3

2b/3 = 8

b = 12, h = 20