Question 703934
Find the equation of the parabola with vertex (-2,0) and y intercept 4. 
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Standard form of parabola: y=A(x-h)2+k, (h,k)=(x,y) coordinates of the vertex
For given problem:
y=A(x+2)^2+0
solve for A using coordinates of the y-intercept (0,4)
4=A(0+2)^2
4A=4
A=1
equation: y=(x+2)^2