<PRE><B>Question 703935</B>
Find the equation of the parabola with vertex (-2,0) and y intercept 4

{{{graph(400,240,-10,10,-2,10,(x+2)^2)}}}

y = a(x-h)² + k

Substitute (h,k) = (-2,0) and (x,y) = (0,4)

4 = a(0-(-2))² + 0

4 = a(2)²

4 = 4a

1 = a

Substitute for just a, h and k, not x or y

y = a(x-h)² + k

y = 1(x-(-2))² + 0

y = (x+2)²

Or you can multiply that out

y = x²+4x+4</PRE>