Question 703801
Four consecutive integers: n, n+1, n+2, n+3.


Find four consecutive integers such that 


the sum of the two largest (n+2+n+3), subtracted from (-(n+2+n+3)), twice the sum of the two smallest (2*(n+n+1)), is 15.


{{{2(n+(n+1))-((n+2)+(n+3))=15}}}
Solve for n, find the other three integers.
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Answer: 9, 10, 11, 12