Question 703727
Let the radius be denoted by {{{ r }}} then:
{{{ area=pi*r^2 }}}
{{{ circumference=2pi*r }}}


area is 3 times greater than the circumference? So
{{{ area = 3*circumference }}}
{{{ pi*r^2 = 3*2pi*r }}}


We can cancel a factor of {{{ pi }}} giving:
{{{ r^2 = 6r }}}
{{{ r^2 - 6r = 0 }}}
{{{ r(r-6) = 0 }}}

Giving two solutions: {{{r=0}}} or {{{r=6}}} of which only {{{r=6}}} is relevant to problem.