Question 703564
    Log base 2 (8x) - log base 2 (x squared minus 1) = log base 2 3
{{{log(2,8x) - log(2,x^2-1) = log(2,3)}}}
{{{log(2,8x/(x^2-1)) = log(2,3)}}}
{{{8x/(x^2-1) = 3}}}
{{{8x = 3(x^2-1)}}}
{{{8x = 3x^2-3)}}}
{{{0 = 3x^2-8x-3}}}
{{{0 = (3x+1)(x-3)}}}
x = {-1/3, 3}
we can throw out the negative solution (extraneous) leaving:
x = 3