Question 703515
The equation of line with in intercept form is 

{{{(x/a) +(y/b)=1}}}


{{{(x/-3) + (y/4) =1}}}


multiply equation by LCD -12
so 4x-3y=-12

3y=4x-12
y = 4/3 x -4

slope = m= 4/3

Perpendicular line will have slope which is  negative reciprocal of 4/3
= -3/4

The line is passing through (-3,0)

equation of line will be

(y-y1) = m(x-x1)

y-(-3)=-3/4(x-0)

y+3= -3/4 x 

y= -3/4 x -3