Question 62580
Let f(x)= 2x-3 and g(x)= x^2+2x  find the following expressions


 f(1) substitute 1 in for x in f(x) and simplify.
f(1)=2(1)-3
f(1)=2-3
{{{highlight(f(1)=-1)}}}
:
 g(-2) substitute -2 in for x in g(x) and simplify.
{{{g(-2)=(-2)^2+2(-2)}}}
g(-2)=4-4
{{{highlight(g(-2)=0)}}}  
:
 f(3a)  substitute 3a in for x in f(x) and simplify.
f(3a)=2(3a)-3
{{{highlight(f(3a)=6a-3)}}}
:
 f(3)+g(4) substitute 3 in for x in f(x) and 4 in for x in g(x) and add them together.
{{{f(3)+g(4)=(2(3)-3)+((4)^2+2(4))}}}
{{{f(3)+g(4)=6-3+16+8}}}
{{{highlight(f(3)+g(4)=27)}}}

Happy Calculating!!!!