<PRE><B>Question 703199</B>
Assume the number takes the expanded form, x*10+y*1, and the digits are x and y.


(1)  Either x-y=1, OR  y-x=1.
(2)  The other description translates to 10x+y=1+5(x+y)


Using equation #2, 10x+y=1+5x+5y,
5x+y=1+5y
5x-4y=1


If we now chose from eq.#1, y-x=1, we find x=y-1.  Substitute this into 5x-4y=1.
5(y-1)-4y=1
couple more steps,
y=6
Therefore x=5


Answer:  56</PRE>