Question 62576
How do I find the symmetry for y=-x^2+6x-9
For quadratic equation written in standard form {{{highlight(y=ax^2+bx+c)}}}, you can find the axis of symmetry with the formula {{{highlight(x=-b/2a)}}}.
For this equation: a=-1, b=6 and c=-9
{{{x=-(6)/2(-1)}}}
{{{x=-6/-2}}}
{{{x=3}}}
Happy Calculating!!!
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