<PRE><B>Question 703189</B>
6 married couples are there in a room.
If 2 people are chosen at random find the probability that 
(a)they are married
# of ways to succeed: 6
# of possible pairs: 12C2 = 66
P(choose married couple) = 6/66 = 1/11
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(b)one is a male and the other is a female
# of ways to succeed: 6*6 = 36
# of possible pairs: 66
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P(a male and a female) = 36/66 = 6/11
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cheers,
Stan H.
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