Question 703217
(a^2)^3/b^3÷(a/b^2)^-2 simplifies to a^8/b^7
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(a^6)/(b^3) / (b^2/a)^2 
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= (a^6/b^3) / (b^4/a^2)
Invert the denominator and multiply to get:
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= (a^6/b^3) * (a^2/b^4)
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= a^8/b^7
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Cheers,
Stan H.