Question 703188
You say the radius is "(2+sqrt(xy^5))meter". That is {{{(2+sqrt(xy^5))meter}}}.

{{{area = pi*r^2}}}
{{{area=pi*(2+sqrt(xy^5))^2}}}
={{{pi*(2^2+4*sqrt(xy^5)+x*y^5)}}}
={{{pi*(4+4*y^2*sqrt(xy)+x*y^5)}}}


In case of confusion in the final step, for the middle term,
know that {{{sqrt(N^2)=N}}}.  Every TWO occurences of the same factor under the square root radical can be taken outside as a single occurence.
{{{4*sqrt(x*Y^5)=4*sqrt(x*y^2*y^2*y)}}}
={{{4*y*y*sqrt(x*y)}}}
={{{4*y^2*sqrt(x*y)}}}