Question 702557
2^(x+3)= 6^(x-1)
take the log of both sides:
log(2^(x+3)) = log(6^(x-1))
(x+3)*log(2) = (x-1)*log(6)
xlog(2)+3log(2) = xlog(6)-log(6)
xlog(2) = xlog(6)-log(6)-3log(2)
xlog(2) - xlog(6) = -log(6)-3log(2)
multiplying both sides by -1:
xlog(6) - xlog(2) = log(6)+3log(2)
x(log(6) - log(2)) = log(6)+3log(2)
x = (log(6)+3log(2)) / (log(6) - log(2))
x = (1.681241237) / (0.47712125472)
x = 3.52372