<PRE><B>Question 702398</B>
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Let *[tex \LARGE s] represent the measure of the side of the original square.  Then *[tex \LARGE s\ +\ 3] is the measure of the side of the larger square.


The area of the larger square is then *[tex \LARGE (s\ +\ 3)^2], which is 69 square yards larger than the area of the smaller square which is *[tex \LARGE s^2]


Therefore


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (s\ +\ 3)^2\ =\ s^2\ +\ 69]


Solve for *[tex \LARGE s]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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