Question 702377


{{{xa+xb+3a+3b}}} Start with the given expression



{{{(xa+xb)+(3a+3b)}}} Group the terms in two pairs



{{{x(a+b)+3(a+b)}}} Factor out the GCF {{{x}}} out of the first group. Factor out the GCF {{{3}}} out of the second group



{{{(x+3)(a+b)}}} Since we have the common term {{{a+b}}}, we can combine like terms



So {{{xa+xb+3a+3b}}} factors to {{{(x+3)(a+b)}}}



In other words, {{{xa+xb+3a+3b=(x+3)(a+b)}}}