<PRE><B>Question 702353</B>
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Let *[tex \LARGE w] represent the width.  Then *[tex \LARGE 3w] must represent the length.  Since for any rectangle, *[tex \LARGE P\ =\ 2l\ +\ 2w] you can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(3w)\ +\ 2w\ =\ 160]


Solve for *[tex \LARGE w].  Then since the area is given by the length times the width, calculate *[tex \LARGE 3w^2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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