Question 62524
2 / (3x^4 - 1 )/( 3x^2y + a) / (2x^3p )

=[2/(3x^4-1)] * [2x^3p/(3x^2y+a)]
There are no factors common to numerator and denominator, so
=[4x^3p]/[(3x^4-1)(3x^2y+a)]
Cheers,
Stan H.