Question 62520
Use synthetic division to determine which pair of integers provide both a lower and an upper bound for the zeros of : 
f(x)= 2x^4-14x^3+22x^2+14x-24? 
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-2 )2    -14     22     14    -24
    2    -18     58    -102   +180
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-1 )2    -14     22     14    -24
    2    -16     38    -24      0
Therefore a zero between x=-2 and x=0;
the zero is at x=-1
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0 ) 2    -14    22     14    -24
f(0)=-24
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1 )2    -14    22     14    -24
   2    -12    10     24    0
Therefore a zero between x=0 and x=2;
the zero is at x=1
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There is another zero at x=3 and another
at x=4.
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I'll let you state the lower and upper bounds.
Cheers,
Stan H.