Question 702105
C(n,r) = (n!)/(r!(n-r)!)


C(8,4) = (8!)/(4!*(8-4)!)


C(8,4) = (8!)/(4!*4!)


C(8,4) = (8*7*6*5*4!)/(4!*4!)


C(8,4) = (8*7*6*5)/(4!)


C(8,4) = (8*7*6*5)/(4*3*2*1)


C(8,4) = (1680)/(24)


C(8,4) = 70


So there are 70 ways to do this assuming order doesn't matter.