Question 701875
Note: You have asked several of these questions.
Are you learning anything from the answers provided?
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Given a level of confidence of 99% and a population standard deviation of 13, answer the following:
n = [z*s/E]^2
The 99% determines "z"
std = 13 determines "s"
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(A) What other information is necessary to find the sample size (n)?
You need E---the margin of error
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(B) Find the Maximum Error of Estimate (E) if n = 61.
61 = [2.3263*13/E]^2
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2.3263*13/E = sqrt(61)
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E = 2.3263/sqrt(61)
E = 0.2979
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Cheers,
Stan H.