<PRE><B>Question 62496</B>
One type of gasohol is 10% alcohol( T SAY) and another type is 35% alcohol(F SAY). How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture?
T+F = 400 G......F =  400 - T G....................1
ALCOHOL IN T = T*10/100=0.1T G.....................2
ALCOHOL IN F = F*35/100=0.35F=0.35(400-T)=140-0.35T G.............3
TOTAL ALCOHOL IN THE MIX = 400*25/100=100 G.................4
HENCE
0.1T+140-0.35T=100
0.35T-0.1T=140-100=40
0.25T = 40
T=40/0.25=160 G............IS 10% ALCOHOL IN THE MIX
F=400-160=240 G............IS 35% ALCOHOL IN THE MIX</PRE>