Question 701866
Set up:
Equation 1: {{{B = A + 2}}} (This is the equation for consecutive odd numbers)
Equation 2: {{{7A = 5B + 12}}}
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Plug (A+2) into equation 2 for B
Equation 2: {{{7A = 5B + 12}}}
{{{7A = 5*(A+2) + 12}}}
Multiply the 5 through
{{{7A = 5A + 10 + 12}}}
Combine like terms
{{{7A = 5A + 22}}}
Subtract 5A from both sides
{{{2A = 22}}}
Divide both sides by 2
{{{highlight(A = 11)}}}
Now plug 11 into equation 1 for A
Equation 1: {{{B = A + 2}}}
{{{B = (11) + 2}}}
{{{highlight_green(B = 13)}}}