Question 701838
The sum of three consecutive multiples of 9 is 999.Find these multiples.
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1st: 9(x-1) = 9x-9
2nd: 9x
3rd: 9(x+1) = 9x+9
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Equation:
sum = 999
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27x = 999
x = 37
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1st: 333-9 = 324
2nd: 333
3rd: 333+9 = 342

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Cheers,
Stan H.
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