Question 701787
let first odd integer be x and next odd integer be (x+2)

given 
      x(x+2) = 2{ x+(x+2)}-1
      x^2+2x =4x+3
       x^2-2x-3=0
      (x+1)(x-3) = 0
  x=-1 or x=3   but x cant be -1 because given x is an odd integer...hence x=3

then x+2= 3+2=5

hence  two required odd integers are 3 and 5