Question 701683
I have a 30-60-90 triangle, and the long leg is 33 degrees. How do I find the short leg and hypotenuse?


When the longer leg of a 30-60-90 triangle is known, its shorter leg = {{{longer_leg/sqrt(3)}}}, or in this case: {{{33/sqrt(3)}}} ----- {{{(33sqrt(3))/(sqrt(3) * sqrt(3))}}} ---- {{{33sqrt(3)/(sqrt(9))}}} ----- {{{33sqrt(3)/3}}} ----- {{{11cross(33)sqrt(3)/cross(3)}}} ----- {{{11sqrt(3)}}}, or {{{highlight_green(19.05255888)}}}


When the longer leg of a 30-60-90 triangle is known, its hypotenuse = {{{2(longer_leg/sqrt(3))}}}, or in this case: {{{2*11sqrt(3)}}}, or {{{22sqrt(3)}}}, or 2 *19.05255888 ≈ {{{highlight_green(38.1)}}}


You can do the check!!


Send comments and “thank-yous” to “D” at MathMadEzy@aol.com