Question 701654
{{{(1/3)(9b+1)=b-1}}} Start with the given equation



{{{9b+1=3(b-1)}}} Multiply both sides by 3.



{{{9b+1=3b-3}}} Distribute.



{{{9b=3b-3-1}}} Subtract {{{1}}} from both sides.



{{{9b-3b=-3-1}}} Subtract {{{3b}}} from both sides.



{{{6b=-3-1}}} Combine like terms on the left side.



{{{6b=-4}}} Combine like terms on the right side.



{{{b=(-4)/(6)}}} Divide both sides by {{{6}}} to isolate {{{b}}}.



{{{b=-2/3}}} Reduce.



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Answer:


So the solution is {{{b=-2/3}}}