Question 701492

if you have this {{{3/4+i}}} than you have complex number and only what you can do is write real part as decimal number {{{0.75+i}}}

but, if you have this {{{3/(4+i)}}} than you multiply both nominator and denominator by  {{{(4-i)}}} to eliminate {{{i}}} from denominator


{{{3/(4+i)}}}


{{{3(4-i)/((4-i)(4+i))}}}


{{{(12-3i)/(4^2-i^2)}}}


{{{(12-3i)/(16-(-1))}}}


{{{(12-3i)/(16+1)}}}


{{{(12-3i)/17}}}


{{{12/17-3i/17}}}


{{{0.706-0.1771i}}}