Question 701454
{{{(x+1)/(x^2+6x+9) -1/(x-3)}}}


={{{(x+1)/(x+3)^2 - 1/(x-3)}}}


={{{((x+1)(x-3))/(x+3)^2 - 1(x+3)^2/(x-3)}}}


={{{((x^2-3x+x-3) - 1(x+3)^2)/((x+3)^2(x-3))}}}


={{{(x^2-3x+x-3 - (x^2+6x+9))/((x+3)^2(x-3))}}}


={{{(x^2-3x+x-3 -x^2-6x-9))/((x+3)^2(x-3))}}}


={{{(-8x-12)/((x+3)^2(x-3))}}}


={{{-4(2x+3)/((x+3)^2(x-3))}}}