Question 62496
One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture?
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Let amount of 10% solution be "x" gallons; this has 0.10x gals. of alcohol
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Amount of 35% solution is "400-x" gallons; this has 0.35(400-x)=140-0.35x gals
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EQUATION:
alcohol + alcohol = 25%(400) gallons
0.10x+140-0.35x=100
-0.25x=-40
x=160 gallons (amount of 10% solution)
400-x=240 gallons (amount of 35% solution)
Cheers,
Stan H.