<PRE><B>Question 701316</B>
&lt;br&gt;&lt;font face=&quot;Tahoma&quot;&gt;{{{12-4a-3b-ab}}} given&lt;br&gt;

{{{(12-4a)-(3b-ab)}}} group the terms to see if it will work&lt;br&gt;

{{{4*(3-a)-3b*(3-a)}}} factor 4 out of the first group, and 3b out of the second&lt;br&gt;

And you can see that we do have a common term of (3-a).&lt;br&gt;

{{{(4-3b)(3-a)}}} final factored form&lt;br&gt;

Factoring by grouping can be fairly tricky.&lt;br&gt;

But this is a good example of how it works.&lt;br&gt;

It is not the most common of factoring methods, but it is good to be aware of.&lt;br&gt;

I hope this helps!  Keep practicing!  :)&lt;br&gt;

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