<PRE><B>Question 701342</B>
If it takes 2 people 4 hours to complete 1 job, with 1 person working 1.5 times faster than the other.
:
let x = time for the fast person to complete the job (alone)
then
1.5x = time required by the other person alone
:
Let the completed job = 1
:
Each will do a fraction of the job, the two fractions add up to 1
{{{4/x}}} + {{{4/(1.5x)}}} = 1
multiply by 3x to get rid of the denominators, resulting in:
3(4) + 2(4) = 3x
12 + 8 = 3x
20 = 3x
x = 20/3
x = 6{{{2/3}}} hrs for the fast guy alone
:
;
Check this with a calc
{{{4/6.67}}} + {{{4/(1.5*6.67)}}} = .9995 ~ 1 confirms our solution

 </PRE>