Question 701260

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-4,-3\right)]. So this means that {{{x[1]=-4}}} and {{{y[1]=-3}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(2,-3\right)].  So this means that {{{x[2]=2}}} and {{{y[2]=-3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-3--3)/(2--4)}}} Plug in {{{y[2]=-3}}}, {{{y[1]=-3}}}, {{{x[2]=2}}}, and {{{x[1]=-4}}}



{{{m=(0)/(2--4)}}} Subtract {{{-3}}} from {{{-3}}} to get {{{0}}}



{{{m=(0)/(6)}}} Subtract {{{-4}}} from {{{2}}} to get {{{6}}}



{{{m=0}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-4,-3\right)] and *[Tex \LARGE \left(2,-3\right)] is {{{m=0}}}