Question 701258
The cost of six pennants and nine balls is $48. The cost of three balls is $1 more than the cost of one pennant. What are the costs of one pennant and one ball?" 
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Value Equations:
6p + 9b = 48
3b = p + 1
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Substitution:
p = 3b-1
Substitute for "p" and solve for "b":
6(3b-1) + 9b = 48
18b - 6 +  9b = 48
27b = 54
b = $2.00 (cost of 1 ball)
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Solve for "p":
p = 3b-1
p = 3*2-1
p = $5.00 (cost of one pennant)
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Elimination:
6p + 9b = 48
3b = p + 1
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Rearrange 
3b + 2p = 16
3b - p  = 1
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Subtract and solve for "p"
3p = 15
p = $5.00 (pennant)
Solve for "b":
3b - p = 1
3b - 5 = 1
3b = 6
b = $2.00 (ball)
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Cheers,
Stan H.
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