Question 701195
Hopefully your question is {{{sqrt(5x^2-3x)=2x}}}
To solve this we need to square both sides to get rid of that nasty square root on the left hand side.
this will give {{{5x^2-3x=4x^2}}}
rearranging this equation and simplifying we get
{{{x^2-3x=0}}}
we can take out the common factor of x to give
x(x-3)=0
therefore x=0 or x-3=0 i.e. x=3