Question 701158
The general equation of a circle with centre (a,b) and radius r is:
{{{ (x-a)^2 + (y-b)^2 = r^2 }}}


So equation of a circle in with centre at (-2, 1) is:
{{{ (x+2)^2 + (y-1)^2 = r^2 }}}


Circle passes through (3, -2) so:
{{{ (3+2)^2 + (-2-1)^2 = r^2 }}}
{{{ 25 + 9 = r^2 }}}
{{{ 34 = r^2 }}}


Hence, the required equation is:
{{{ (x+2)^2 + (y-1)^2 = 34 }}}