Question 62466
DISTANCE=RATE*TIME SO
D=10T FOR THE FIRST RIDER
FOR THE SECOND RIDER WE HAVE 
D=18(T-3) SEEING AS THE DISTANCES ARE EQUAL WE HAVE 
10T=18(T-3)
10T=18T-54
10T-18T=-54
-8T=-54
T=-54/-8
T=6.75 HOURS AFTER 6:00 AM WHICH MAKES IT 6+6.75 OR  12:45 P.M.