Question 700975
you have 100mL of distilled water and you need to add 20% chlorhexidine solution so that you have a 100mL solution of 0.05% of chlorhexidine.
:
Let x = amt of chloro-something required
:
.20x = .05(x+100)
.20x = .05x + 5
.20x - .05x = 5
.15x = 5
x = 5/.15
x = 33{{{1/3}}} mL of chloro-something required
:
:
Check this
.20(33.33) = .05(133.33)