Question 700953
a. Choose a third animal. Calculate its speed in yards per second. Compare its speed with the speed of the other two animals you chose in Activity 1. 
the first two animals i chose were :
fox 20.53 yards per second
and a coyote 21.02 yards per second 
the third animal i chose is Zebra travels 40 m/hr (19.56 yd/sec) 

a. Compare the zebra's speed with the speed of the two other animals
zebra-coyote = 19.56-21.02 = -1.46 yd/sec
zebra-fox = 19.56 - 20.53 = -0.97 yd/
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b. Decide which two animals should get head starts and how much of a head start each should get.
If you want the race to be fair, the slowest animal needs the greater headstart.
Zebra is slowest: 19.56 yd/sec
then fox is next slowest: 20.53 yd/sec
coyote is fastest:21.02 yd/sec
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How much of a head start depends on the length of the race
If the race is 100 yds, coyote will take dist/rate = 100/21.02  = 4.57 seconds
fox will take 100/20.53 = 4.87 sec
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So the fox needs a 4.87-4.57 = 0.3 sec head start.
At the fox's rate that is a head start of 0.3*20.53 = 6.159 yards
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Do the same for the zebra to figure out it's head start.
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Write three equations relating distance from the starting line to time. 
c. Graph all three equations on the same coordinate plane.
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Cheers,
Stan H.
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