Question 700950


{{{Area =(1/2)*b*h}}} where {{{b}}} is base and {{{h}}} is height

if given {{{a=b=c=12}}}, means you have an Equilateral Triangle and base {{{b=12}}}

now we need to calculate height {{{h}}} which could be find using Pythagorean theorem because it divides equilateral triangle into two right angle triangles; so,

{{{h^2=a^2-(b/2)^2}}}

{{{h^2=12^2-(12/2)^2}}}

{{{h^2=12^2-6^2}}}

{{{h^2=144-36}}}

{{{h^2=108}}}

{{{h=sqrt(108)}}}

{{{h=10.39}}}...we need only positive root because height could be only positive number


then, the area will be:

{{{Area =(1/2)*12*10.39}}}

{{{Area =6*10.39}}}

{{{Area =62.34}}}