Question 700755
sketch a graph of the quadratic function with the given vertex and through the given point.then write the equation of the parabola in vertex form. 
1. vertex(-3,-2);point(1,2)
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Standard form of equation parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.
For given parabola:
y=A(x+3)^2-2
find A using coordinates of given point (1,2)
2=A(1+3)^2-2
4=A(4)^2
A=4/16
equation:(1/4)(x+3)^2-2
see graph below:
 {{{ graph( 300, 300, -10, 10, -10, 10, (1/4)(x+3)^2-2) }}}