Question 700719
Write an equation in slope-intercept form of the line that passes through the points: ( -1/2 , 4 ) , ( 6 , -1/3 ). 
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equation for a line: y=mx+b, m=slope, b=y-intercept
slope=∆y/∆x=(-(1/3)-4)/(6-(-1/2))=(-13/3)/(13/2)=-2/3
equation: y=-2x/3+b
solve for b using coordinates of point (-1/2,4)
4=-2*(-1/2)/3+b
4=1/3+b
b=11/3
equation: y=-2x/3+11/3