<PRE><B>Question 700669</B>
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The number of diagonals in a polygon is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{n(n\ -\ 3)}{2}]


So for your problem:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{n(n\ -\ 3)}{2}\ =\ 464]


Solve the resulting quadratic for *[tex \LARGE n].  Hint:  29 times -32 = -928



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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